-4.9x^2+30x-10=0

Solution for -4.9x^2+30x-10=0 equation:

-4.9x^2+30x-10=0

a = -4.9; b = 30; c = -10;
Δ = b2-4ac
Δ = 302-4·(-4.9)·(-10)
Δ = 704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{704}=\sqrt{64*11}=\sqrt{64}*\sqrt{11}=8\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-8\sqrt{11}}{2*-4.9}=\frac{-30-8\sqrt{11}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+8\sqrt{11}}{2*-4.9}=\frac{-30+8\sqrt{11}}{-9.8}
$